Masala A. HTTS
Shartida berilgandek N soniniberiladi, berilgan N sonining uzunligini toq va har bir raqamlari ham toq bo'lsa shuning o'zi yetarli bo'ladi.
C++ dasturlash tilida yechim:
#include<bits/stdc++.h>
using namespace std;
int main(){
long long n,y;
cin>>n;
int s=0;
while(n>0){
y=n%10;s += 1;
if(y%2==0){
cout<<"NO"; return 0;
}
n/=10;
}
if(s%2==1) cout<<"YES";
else cout<<"NO";
}
Python dasturlash tilida yechim:
n = int(input())
s = 0
while n > 0:
y = n % 10
s += 1
if y % 2 == 0:
print("NO")
exit()
n //= 10
if s % 2 == 1:
print("YES")
else:
print("NO")
Masala B. Tarvuz
Algoritm: Matematika
C++ dasturlash tilida yechim:
#include <bits/stdc++.h>
using namespace std;
int main(){
long double a;
int b, c;
cin >> a >> b >> c;
cout << fixed << setprecision(5) << a*(100-b)/(100-c);
return 0;
}
Python dasturlash tilida yechim:
a, b, c = map(int, input().split())
print(a*(100-b)/(100-c))
Masala C. Maximum sum
Algoritm: Two pointers, Perebor, Tartiblash.
#include<bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
vector<int> a(n);
for(int i=0; i<n; i++) cin >> a[i];
sort(a.begin(), a.end());
vector<int> sum(n, 0);
sum[0] = a[0];
for (int i = 1; i < n; i++) {
sum[i] = sum[i - 1] + a[i];
}
int l, r;
int ans = 0;
for (int i = 0; i <= k; i++) {
l = 2 * i;
r = n - k + i - 1;
ans = max(ans, sum[r] - sum[l] + a[l]);
}
cout << ans << endl;
}
Python dasturlash tilida yechim:
n, k = map(int, input().split())
a = list(map(int, input().split()))
a.sort()
sum = [0] * n
sum[0] = a[0]
for i in range(1, n):
sum[i] = sum[i - 1] + a[i]
ans = 0
for i in range(k + 1):
l = 2 * i
r = n - k + i - 1
ans = max(ans, sum[r] - sum[l] + a[l])
print(ans)
Masala D. O'zgartirishlar
Algoritm: Prefiks sum.
#include<bits/stdc++.h>
using namespace std;
#define yes cout << "YES" << endl
#define no cout << "NO" << endl
#define int long long
signed main() {
int n, q;
cin >> n >> q;
vector<int> a(n);
vector<int> sum(n);
for (int i = 0; i < n; ++i) cin >> a[i];
sum[0] = a[0];
for (int i = 1; i < n; ++i) sum[i] = sum[i - 1] + a[i];
while (q--) {
int l, r, k;
cin >> l >> r >> k;
l--;
r--;
if ((sum[n - 1] - (sum[r] - sum[l] + a[l]) + k * (r - l + 1)) % 2 == 0) yes;
else no;
}
}
Python dasturlash tilida yechim:
n, q = map(int, input().split())
a = list(map(int, input().split()))
sum = [0] * n
sum[0] = a[0]
for i in range(1, n):
sum[i] = sum[i - 1] + a[i]
for i in range(q):
l, r, k = map(int, input().split())
l -= 1
r -= 1
if ((sum[n - 1] - (sum[r] - sum[l] + a[l]) + k * (r - l + 1)) % 2 == 0):
print("YES")
else:
print("NO")
Masala E. O'rmon va daraxtlar
Algoritm: Binary search.
#include<bits/stdc++.h>
using namespace std;
#define yes cout << "YES" << endl
#define no cout << "NO" << endl
#define int long long
signed main() {
int n, m;
cin >> n >> m;
vector<int> a(n);
for (int &i : a) cin >> i;
sort(a.begin(), a.end());
int l = 1, r = 1e9;
while(l < r) {
int h = (l + r) / 2;
int s = 0;
for (int i = 0; i < n; i++) {
if (a[i] > h) {
s += a[i] - h;
}
}
if (s >= m) {
l = h + 1;
} else {
r = h;
}
}
cout << l - 1 << endl;
}
Python dasturlash tilidagi yechim:
n, m = map(int, input().split())
a = list(map(int, input().split()))
a.sort()
l = 1
r = 10 ** 9
while l < r:
h = (l + r) // 2
s = 0
for i in range(n):
if a[i] > h:
s += a[i] - h
if s >= m:
l = h + 1
else:
r = h
print(l - 1)
Masala F. Robolandiyada saralash
#include<bits/stdc++.h>
using namespace std;
#define yes cout << "YES" << endl
#define no cout << "NO" << endl
#define int long long
#define endl "\n"
signed main() {
int n;
cin >> n;
vector<vector<int>> v(n, vector<int>(4,0));
for(int i = 0; i < n; i++) {
int a, b, c;
cin >> a >> b >> c;
v[i][0] = -a;
v[i][1] = -b;
v[i][2] = c;
v[i][3] = i + 1;
}
sort(v.begin(), v.end());
for (auto i : v) {
cout << i[3] << " ";
}
}
Python dasturlash tilida yechim:
n = int(input())
v = []
for i in range(n):
a, b, c = map(int, input().split())
v.append([-a, -b, c, i + 1])
v.sort()
for i in v:
print(i[3], end=' ')
Masala G. Haqiqiy tenglama.
Algoritm: Binary search
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define ld long double
signed main() {
ld c;
int n;
cin >> c >> n;
ld l = 0, r = 1e12;
while(r - l > 1e-10) {
ld mid = (l + r) / 2;
if (n * pow(mid, n) + pow(mid, 1.0/n) < c) {
l = mid;
} else {
r = mid;
}
}
cout << fixed << setprecision(7) << (double)l << endl;
}
Python dasturlash tilida yechim:
c = float(input())
n = int(input())
left = 0
right = 1e12
while right - left > 1e-11:
mid = (left + right) / 2
if n * pow(mid, n) + pow(mid, 1.0 / n) < c:
left = mid
else:
right = mid
print(f'{left:0.7f}')
Masala H. AVL daraxt.
Algoritm: Dinamik dasturlash, Matrix pow, Ikkilik daraja
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define mod 1000000007
int32_t main() {
int n;
cin >> n;
n = n + 3;
int a[2][2] = {{0,1}, {1,1}};
int r[2][2] = {{1,0}, {0,1}};
while(n>0){
if(n%2 == 1){
int c[2][2] = {{0,0}, {0,0}};
for(int i=0; i<2; i++){
for(int j=0; j<2; j++){
for(int k=0; k<2; k++){
c[i][j] = (c[i][j] + r[i][k] * a[k][j])%mod;
}
}
}
for(int i=0; i<2; i++){
for(int j=0; j<2; j++){
r[i][j] = c[i][j];
}
}
n = n - 1;
}
else{
int c[2][2] = {{0,0}, {0,0}};
for(int i=0; i<2; i++){
for(int j=0; j<2; j++){
for(int k=0; k<2; k++){
c[i][j] = (c[i][j] + a[i][k] * a[k][j])%mod;
}
}
}
for(int i=0; i<2; i++){
for(int j=0; j<2; j++){
a[i][j] = c[i][j];
}
}
n = n / 2;
}
}
cout << r[1][0] - 1 << endl;
return 0;
}
Python dasturlash tilida yechim:
import math
def f(a,b):
mod = 10**9+7
c = [[0,0], [0,0]]
for i in range(2):
for j in range(2):
for k in range(2):
c[i][j] = (c[i][j] + a[i][k] * b[k][j])%mod
return c
def fib(n):
a = [[0,1], [1,1]]
r = [[1,0], [0,1]]
while(n>0):
if n%2 == 1:
r = f(r,a)
n = n // 2
a = f(a,a)
return r[1][0]
n = int(input())
n = n + 3
print(fib(n)-1)
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